[TriLUG] possible awk/grep question
dave at jamsoft.com
Sun Dec 30 19:49:18 EST 2007
If a user means their default group is 100 - for fun, here's a variation
using bash alone:
(while read USR F2 F3 GID F5; do
if [ $GID -eq 100 ]; then
done) < /etc/passwd
Joseph Mack NA3T wrote:
> I need to find all "users" on a machine.
> It occurs to me that I could find this by looking for all
> lines in /etc/passwd that have "100" in the 4th field, but I
> don't know how to do that in bash/awk/grep, at least not in
> a small number of lines. If I can do that, then I have other
> uses for a script that can find all lines that match in a
> certain field. Anyone know how to do that?
> Failing that, anyone know how to find the members of a group
> (eg users) by any method?
> Thanks Joe
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