[TriLUG] Need some help parsing a file

[Peter Neilson]

Your regex fails if any filename starts with one or more digits followed  
by spaces. The digits and the ensuing spaces will be gobbled greedily.

If instead we aim at seeing at least three spaces between the time-of-day  
and the size of the file, and a single space following the size of the  
file, then this might work:

cat filename.txt |perl -pe "s/^.+\s\s\s[\d,]+\s//"

Testing with a filename of " 4    his is filename 2.sh" and a stripped  
leading zero on the time-of-day I get this:

$ cat filename.txt
11/09/2013  11:49 AM         7,887,098 this is filename 1.txt
11/05/2013   8:09 PM        11,652,690  4    his is filename 2.sh
$ cat filename.txt |perl -pe "s/^.+\s\s\s[\d,]+\s//"
this is filename 1.txt
  4    his is filename 2.sh
$

My example allows the notion that a filenames might stupidly start with a  
space, something that IS legal in Unix-like systems. I restricted the  
regex to look for a single space after the size of the file. There are  
still some failing cases where the filename starts with TWO (or more)  
spaces. *SIGH*

On Sun, 29 Dec 2013 22:48:18 -0500, William Sutton <william at trilug.org>  
wrote:

> still relies on file listings starting in column 40.  You really want  
> awk+sed for this sort of thing, but I never learned awk.  So...
>
> cat filename.txt |perl -pe "s/^.+[\d,]+\s+//"
>
> :-)
>
> William Sutton
>
> On Sun, 29 Dec 2013, Peter Neilson wrote:
>
>> On Sun, 29 Dec 2013 21:13:17 -0500, Dewey Hylton <plug at hyltown.com>  
>> wrote:
>>
>>> try this:
>>>  cut -c40- < filename.txt
>>
>> Doesn't use sed, but it's better than mine.
>> -- This message was sent to: William <william at trilug.org>
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